What is factor 3n^3-4n^2+9n-12 ?

The solution to factor 3n^3-4n^2+9n-12 is (3n-4)(n^2+3)

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factor 3n^3-4n^2+9n-12

factor

3 n^{3} - 4 n^{2} + 9 n - 12

(3 n - 4) (n^{2} + 3)

Solution steps

3 n^{3} - 4 n^{2} + 9 n - 12

= (3 n^{3} - 4 n^{2}) + (9 n - 12)

Factor out

n^{2}

from

3 n^{3} - 4 n^{2} : n^{2} (3 n - 4)

Factor out

3

from

9 n - 12 : 3 (3 n - 4)

= n^{2} (3 n - 4) + 3 (3 n - 4)

Factor out common term

3 n - 4

= (3 n - 4) (n^{2} + 3)

(\frac{x}{4}) + 8 = 38

2 - 5 ∣ 5 x - 5 ∣ = 73

\frac{c ^{2} d ^{- 3}}{c ^{3} d ^{- 1}}

\frac{1}{\frac{6}{3}}

(\frac{27}{64})^{- \frac{2}{3}}

What is factor 3n^3-4n^2+9n-12 ?
The solution to factor 3n^3-4n^2+9n-12 is (3n-4)(n^2+3)