What are the solutions to the equation x^2+14x+34=5 ?

The solutions to the equation x^2+14x+34=5 are x=-7+2sqrt(5),x=-7-2sqrt(5)

Find the zeros of x^2+14x+34=5

The zeros of x^2+14x+34=5 are x=-7+2sqrt(5),x=-7-2sqrt(5)

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x^{2} + 14 x + 34 = 5

x = - 7 + 25, x = - 7 - 25

Solution steps

x^{2} + 14 x + 34 = 5

Move

5

to the left side

x^{2} + 14 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 29 = 45

x_{1, 2} = \frac{- 14 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 14 - 4 5}{2 \cdot 1}

x = \frac{- 14 + 4 5}{2 \cdot 1} : - 7 + 25

x = \frac{- 14 - 4 5}{2 \cdot 1} : - 7 - 25

The solutions to the quadratic equation are:

x = - 7 + 25, x = - 7 - 25

\frac{1}{3} p^{- 2} q^{3} r

t^{3} - 25 t

3 x + 7 = 1

- \frac{7}{4} \geq \frac{3 - 5 x}{5}

x^{4} - 4 x^{3} - 14 x^{2} + 65 x - 100

What are the solutions to the equation x^2+14x+34=5 ?
The solutions to the equation x^2+14x+34=5 are x=-7+2sqrt(5),x=-7-2sqrt(5)
Find the zeros of x^2+14x+34=5
The zeros of x^2+14x+34=5 are x=-7+2sqrt(5),x=-7-2sqrt(5)