What are the solutions to the equation 0=2x^2+3x ?

The solutions to the equation 0=2x^2+3x are x=0,x=-3/2

Find the zeros of 0=2x^2+3x

The zeros of 0=2x^2+3x are x=0,x=-3/2

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0 = 2 x^{2} + 3 x

x = 0, x = - \frac{3}{2}

Solution steps

0 = 2 x^{2} + 3 x

Switch sides

2 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 2}, x_{2} = \frac{- 3 - 3}{2 \cdot 2}

x = \frac{- 3 + 3}{2 \cdot 2} : 0

x = \frac{- 3 - 3}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

- 4 (3 x + 2) = - 3 (4 x + 5)

x + 9 \geq 9 and x + 6 \leq 5

\frac{2}{3} x < 14

x^{2} - 3 x - 40 \geq 0

What are the solutions to the equation 0=2x^2+3x ?
The solutions to the equation 0=2x^2+3x are x=0,x=-3/2
Find the zeros of 0=2x^2+3x
The zeros of 0=2x^2+3x are x=0,x=-3/2