What are the solutions to the equation solvefor y,y2x-y=0 ?

The solutions to the equation solvefor y,y2x-y=0 are y= 1/x ,y=0;\quad x\ne 0

Find the zeros of solvefor y,y2x-y=0

The zeros of solvefor y,y2x-y=0 are y= 1/x ,y=0;\quad x\ne 0

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solve for

y, y^{2} x - y = 0

y = \frac{1}{x}, y = 0; x \neq = 0

Solution steps

y^{2} x - y = 0

Write in the standard form

a x^{2} + b x + c = 0

x y^{2} - y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 x \cdot 0}{2 x}

(- 1)^{2} - 4 x \cdot 0 = 1

y_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 x}; x \neq = 0

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 1}{2 x}, y_{2} = \frac{- ( - 1 ) - 1}{2 x}

y = \frac{- ( - 1 ) + 1}{2 x} : \frac{1}{x}

y = \frac{- ( - 1 ) - 1}{2 x} : 0

The solutions to the quadratic equation are:

y = \frac{1}{x}, y = 0; x \neq = 0

I n (2 x + 13 x + 15) = 0

(q - 3) (a + 4) = 0

(1 - x) y = 0

4 t^{2} (u - 1)^{3} = 0

2 r s^{2} + 4 rs + 2 r = 0

What are the solutions to the equation solvefor y,y2x-y=0 ?
The solutions to the equation solvefor y,y2x-y=0 are y= 1/x ,y=0;\quad x\ne 0
Find the zeros of solvefor y,y2x-y=0
The zeros of solvefor y,y2x-y=0 are y= 1/x ,y=0;\quad x\ne 0