What is ((3x^7y^9)/(5x^5y^2))^{-4} ?

The solution to ((3x^7y^9)/(5x^5y^2))^{-4} is (625)/(81x^8y^{28)}

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simplify ((3x^7y^9)/(5x^5y^2))^{-4}

simplify

(\frac{3 x ^{7} y ^{9}}{5 x ^{5} y ^{2}})^{- 4}

\frac{625}{81 x ^{8} y ^{28}}

Solution steps

(\frac{3 x ^{7} y ^{9}}{5 x ^{5} y ^{2}})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{3 x ^{7} y ^{9}}{5 x ^{5} y ^{2}})^{- 4} = \frac{1}{( \frac{3 x ^{7} y ^{9}}{5 x ^{5} y ^{2}} ) ^{4}}

= \frac{1}{( \frac{3 x ^{7} y ^{9}}{5 x ^{5} y ^{2}} ) ^{4}}

Simplify

(\frac{3 x ^{7} y ^{9}}{5 x ^{5} y ^{2}})^{4} : \frac{81 x ^{8} y ^{28}}{625}

= \frac{1}{\frac{81 x ^{8} y ^{28}}{625}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{625}{81 x ^{8} y ^{28}}

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What is ((3x^7y^9)/(5x^5y^2))^{-4} ?
The solution to ((3x^7y^9)/(5x^5y^2))^{-4} is (625)/(81x^8y^{28)}