What is the answer to (x^2-4)(y^2-9)=0 ?

The answer to (x^2-4)(y^2-9)=0 is x=2,x=-2,y=3,y=-3

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(x^2-4)(y^2-9)=0

(x^{2} - 4) (y^{2} - 9) = 0

x = 2, x = - 2, y = 3, y = - 3

Solution steps

(x^{2} - 4) (y^{2} - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} - 4 = 0 or y^{2} - 9 = 0

Solve

x^{2} - 4 = 0 : x = 2, x = - 2

Solve

y^{2} - 9 = 0 : y = 3, y = - 3

The solutions are

x = 2, x = - 2, y = 3, y = - 3

(D - 2 I)^{3} y = 0

2 t (u - 1)^{4} = 0

- 4 y - (x^{4} + 7 x^{2} + 10) y = 0

(x^{2} + 9) y^{1} + x y = 0

u \cdot v = 0

What is the answer to (x^2-4)(y^2-9)=0 ?
The answer to (x^2-4)(y^2-9)=0 is x=2,x=-2,y=3,y=-3