What are the solutions to the equation t^2-20t+100-400=0 ?

The solutions to the equation t^2-20t+100-400=0 are t=30,t=-10

Find the zeros of t^2-20t+100-400=0

The zeros of t^2-20t+100-400=0 are t=30,t=-10

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t^{2} - 20 t + 100 - 400 = 0

t = 30, t = - 10

Solution steps

t^{2} - 20 t + 100 - 400 = 0

Refine

t^{2} - 20 t - 300 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 300 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 300) = 40

t_{1, 2} = \frac{- ( - 20 ) \pm 40}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 20 ) + 40}{2 \cdot 1}, t_{2} = \frac{- ( - 20 ) - 40}{2 \cdot 1}

t = \frac{- ( - 20 ) + 40}{2 \cdot 1} : 30

t = \frac{- ( - 20 ) - 40}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

t = 30, t = - 10

x^{2} + 3 x > 4

\frac{72}{64}

- 3 (2 x + 7) + (- 5 + 6) - 8 (- 1 - 2 x) - (x - 3) = 0 - 8

585

lo g_{3} (9) = x

What are the solutions to the equation t^2-20t+100-400=0 ?
The solutions to the equation t^2-20t+100-400=0 are t=30,t=-10
Find the zeros of t^2-20t+100-400=0
The zeros of t^2-20t+100-400=0 are t=30,t=-10