What is the answer to (x^2+1)(y^2+1)=0 ?

The answer to (x^2+1)(y^2+1)=0 is No Solution for x,y\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2+1)(y^2+1)=0

(x^{2} + 1) (y^{2} + 1) = 0

No Solution for x, y \in R

Solution steps

(x^{2} + 1) (y^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 1 = 0 or y^{2} + 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

y^{2} + 1 = 0 : y = i, y = - i

The solutions are

Remove complex solutions:

x = i, x = - i, y = i, y = - i

No Solution for x, y \in R

s v (s) + 2 v (s) = 0

e^{2 x} 2 y = 0

0 = x I n x

(x^{2} D^{2} + x D) y = 0

BC = 0, 8 D C = 2, 24

What is the answer to (x^2+1)(y^2+1)=0 ?
The answer to (x^2+1)(y^2+1)=0 is No Solution for x,y\in\mathbb{R}