What is 12-5x-2x^2>= 0 ?

The solution to 12-5x-2x^2>= 0 is -4<= x<= 3/2

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12-5x-2x^2>= 0

12 - 5 x - 2 x^{2} \geq 0

- 4 \leq x \leq \frac{3}{2}

Solution steps

12 - 5 x - 2 x^{2} \geq 0

Factor

12 - 5 x - 2 x^{2} : - (2 x - 3) (x + 4)

- (2 x - 3) (x + 4) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (2 x - 3) (x + 4)) (- 1) \leq 0 \cdot (- 1)

Simplify

(2 x - 3) (x + 4) \leq 0

Identify the intervals

- 4 \leq x \leq \frac{3}{2}

x^{3} + 7 x^{2} + 16 x + 12

5 x - 8 x - 14 = 1

3 y^{4} - 75 x^{2} y^{2}

2 n \geq 16

\frac{π}{6} \cdot 4