What is the answer to ny((2-x)^3-(2-x))=0 ?

The answer to ny((2-x)^3-(2-x))=0 is y=0,x=2,x=1,x=3;\quad n\ne 0

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ny((2-x)^3-(2-x))=0

n y ((2 - x)^{3} - (2 - x)) = 0

y = 0, x = 2, x = 1, x = 3; n \neq = 0

Solution steps

n y ((2 - x)^{3} - (2 - x)) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or (2 - x)^{3} - (2 - x) = 0

y = 0

Solve

(2 - x)^{3} - (2 - x) = 0 : x = 2, x = 1, x = 3

The solutions are

y = 0, x = 2, x = 1, x = 3; n \neq = 0

(x + 7) ∣ x - 15 ∣ = 0

I n x = 0

x, x h = 0

(x - 1) y = 0

3 y x^{2} - 2 y x = 0, x^{3} - x^{2} = 0

What is the answer to ny((2-x)^3-(2-x))=0 ?
The answer to ny((2-x)^3-(2-x))=0 is y=0,x=2,x=1,x=3;\quad n\ne 0