What are the solutions to the equation 16x^2+4=16x ?

The solutions to the equation 16x^2+4=16x are x= 1/2

Find the zeros of 16x^2+4=16x

The zeros of 16x^2+4=16x are x= 1/2

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16 x^{2} + 4 = 16 x

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

16 x^{2} + 4 = 16 x

Move

16 x

to the left side

16 x^{2} + 4 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} - 16 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 16 \cdot 4}{2 \cdot 16}

(- 16)^{2} - 4 \cdot 16 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 16 )}{2 \cdot 16}

\frac{- ( - 16 )}{2 \cdot 16} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

(x - 5)^{2} - 9 = 0

16 x^{4 - 1}

m^{6} - 7 m^{4} - 18 m^{2}

(\frac{3}{7})^{0}

2 x^{2} - 12 x - 32 = 0

What are the solutions to the equation 16x^2+4=16x ?
The solutions to the equation 16x^2+4=16x are x= 1/2
Find the zeros of 16x^2+4=16x
The zeros of 16x^2+4=16x are x= 1/2