What is the answer to -400(4x+1)^{99}=0 ?

The answer to -400(4x+1)^{99}=0 is x=-1/4

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-400(4x+1)^{99}=0

- 400 (4 x + 1)^{99} = 0

x = - \frac{1}{4}

Decimal Notation

x = - 0.25

Solution steps

- 400 (4 x + 1)^{99} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

The solution is

x = - \frac{1}{4}

- (1 + x) y = 0

d^{2} y d x^{2} - 2 (d y d x) + 4 y = 0

x, e^{2 x - y} + e^{y - 2 x} = 0

14 x y - 2 x λ = 0

100 - (- 6^{2})

What is the answer to -400(4x+1)^{99}=0 ?
The answer to -400(4x+1)^{99}=0 is x=-1/4
Solve for x: -400(4x+1)^{99}=0
The solution is x=-1/4