What are the solutions to the equation (x^2)/3 =12 ?

The solutions to the equation (x^2)/3 =12 are x=6,x=-6

Find the zeros of (x^2)/3 =12

The zeros of (x^2)/3 =12 are x=6,x=-6

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\frac{x ^{2}}{3} = 12

x = 6, x = - 6

Solution steps

\frac{x ^{2}}{3} = 12

Multiply both sides by

3

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

\frac{x - 5}{4 x - 4} + \frac{2}{x ^{2} - 1} \geq 0

12 n^{2} - 7 n + 1

69 = 1 \cdot 0.037 \cdot (x - 23.45)

3 x^{2} + 17 x + 4 = 9 x

What are the solutions to the equation (x^2)/3 =12 ?
The solutions to the equation (x^2)/3 =12 are x=6,x=-6
Find the zeros of (x^2)/3 =12
The zeros of (x^2)/3 =12 are x=6,x=-6