What is factor 4z^2+4zy+y^2 ?

The solution to factor 4z^2+4zy+y^2 is (2z+y)^2

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factor 4z^2+4zy+y^2

factor

4 z^{2} + 4 zy + y^{2}

(2 z + y)^{2}

Solution steps

4 z^{2} + 4 zy + y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 z^{2} = (2 z)^{2}

4 zy = 2 \cdot 2 zy

= (2 z)^{2} + 2 \cdot 2 zy + y^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 z)^{2} + 2 \cdot 2 zy + y^{2} = (2 z + y)^{2}

= (2 z + y)^{2}

- 4 \times (- 4)

6 \times 6 \times 6

∣ i ∣

\frac{25}{100}

2 \cdot (- 1)