What are the solutions to the equation 1.05x^2-3.1x-6.2=0 ?

The solutions to the equation 1.05x^2-3.1x-6.2=0 are x=(31+sqrt(3565))/(21),x=(31-sqrt(3565))/(21)

Find the zeros of 1.05x^2-3.1x-6.2=0

The zeros of 1.05x^2-3.1x-6.2=0 are x=(31+sqrt(3565))/(21),x=(31-sqrt(3565))/(21)

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1.05 x^{2} - 3.1 x - 6.2 = 0

x = \frac{31 + 3565}{21}, x = \frac{31 - 3565}{21}

Solution steps

1.05 x^{2} - 3.1 x - 6.2 = 0

Multiply both sides by

100

105 x^{2} - 310 x - 620 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 310 ) \pm ( - 310 ) ^{2} - 4 \cdot 105 ( - 620 )}{2 \cdot 105}

(- 310)^{2} - 4 \cdot 105 (- 620) = 103565

x_{1, 2} = \frac{- ( - 310 ) \pm 10 3565}{2 \cdot 105}

Separate the solutions

x_{1} = \frac{- ( - 310 ) + 10 3565}{2 \cdot 105}, x_{2} = \frac{- ( - 310 ) - 10 3565}{2 \cdot 105}

x = \frac{- ( - 310 ) + 10 3565}{2 \cdot 105} : \frac{31 + 3565}{21}

x = \frac{- ( - 310 ) - 10 3565}{2 \cdot 105} : \frac{31 - 3565}{21}

The solutions to the quadratic equation are:

x = \frac{31 + 3565}{21}, x = \frac{31 - 3565}{21}

2124 x^{2} + 5609 x + 5662 = 124000

\frac{b}{- 4} = 5

∣ 5 x - 20 ∣ \leq 15

6 d^{2} - 21 d

ln (e^{7})

What are the solutions to the equation 1.05x^2-3.1x-6.2=0 ?
The solutions to the equation 1.05x^2-3.1x-6.2=0 are x=(31+sqrt(3565))/(21),x=(31-sqrt(3565))/(21)
Find the zeros of 1.05x^2-3.1x-6.2=0
The zeros of 1.05x^2-3.1x-6.2=0 are x=(31+sqrt(3565))/(21),x=(31-sqrt(3565))/(21)