What are the solutions to the equation (50+30x^2)/5 =x^2 ?

The solutions to the equation (50+30x^2)/5 =x^2 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of (50+30x^2)/5 =x^2

The zeros of (50+30x^2)/5 =x^2 are x=sqrt(2)i,x=-sqrt(2)i

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\frac{50 + 30 x ^{2}}{5} = x^{2}

x = 2 i, x = - 2 i

Solution steps

\frac{50 + 30 x ^{2}}{5} = x^{2}

Move

x^{2}

to the left side

5 x^{2} + 10 = 0

Move

10

to the right side

5 x^{2} = - 10

Divide both sides by

5

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

(4 x y^{4})^{3}

\frac{( x + 3 ) ( x - 2 )}{( x + 7 ) ^{2}} \geq 0

2048

\frac{1}{8 4}

7 x = 48

What are the solutions to the equation (50+30x^2)/5 =x^2 ?
The solutions to the equation (50+30x^2)/5 =x^2 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of (50+30x^2)/5 =x^2
The zeros of (50+30x^2)/5 =x^2 are x=sqrt(2)i,x=-sqrt(2)i