What is (3+4i)+(6+2i) ?

The solution to (3+4i)+(6+2i) is 9+6i

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simplify (3+4i)+(6+2i)

simplify

(3 + 4 i) + (6 + 2 i)

9 + 6 i

Solution steps

(3 + 4 i) + (6 + 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (3 + 6) + (4 + 2) i

Simplify

(3 + 6) + (4 + 2) i : 9 + 6 i

= 9 + 6 i

(- 2)^{3} + 100

- i \times i

(x + 5)^{2} - (x - 5)^{2}

\frac{48}{16}

x^{3} - 6 x^{2} + x - 6