What are the solutions to the equation (x+6)(4x-7)=0 ?

The solutions to the equation (x+6)(4x-7)=0 are x=-6,x= 7/4

Find the zeros of (x+6)(4x-7)=0

The zeros of (x+6)(4x-7)=0 are x=-6,x= 7/4

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(x + 6) (4 x - 7) = 0

x = - 6, x = \frac{7}{4}

Solution steps

(x + 6) (4 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or 4 x - 7 = 0

Solve

x + 6 = 0 : x = - 6

Solve

4 x - 7 = 0 : x = \frac{7}{4}

The solutions to the quadratic equation are:

x = - 6, x = \frac{7}{4}

∣ x - 9 ∣ = - 3

3 x^{2} - 4 x = 4

5 \cdot x = 10

\frac{2}{( 2 + 4 ) ^{3}}

- 5 (m - 8) + 12 = 47

What are the solutions to the equation (x+6)(4x-7)=0 ?
The solutions to the equation (x+6)(4x-7)=0 are x=-6,x= 7/4
Find the zeros of (x+6)(4x-7)=0
The zeros of (x+6)(4x-7)=0 are x=-6,x= 7/4