What are the solutions to the equation 5x^2+x-1=0 ?

The solutions to the equation 5x^2+x-1=0 are x=(-1+sqrt(21))/(10),x=(-1-sqrt(21))/(10)

Find the zeros of 5x^2+x-1=0

The zeros of 5x^2+x-1=0 are x=(-1+sqrt(21))/(10),x=(-1-sqrt(21))/(10)

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5 x^{2} + x - 1 = 0

x = \frac{- 1 + 21}{10}, x = \frac{- 1 - 21}{10}

Solution steps

5 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 1) = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 \cdot 5}, x_{2} = \frac{- 1 - 21}{2 \cdot 5}

x = \frac{- 1 + 21}{2 \cdot 5} : \frac{- 1 + 21}{10}

x = \frac{- 1 - 21}{2 \cdot 5} : \frac{- 1 - 21}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 21}{10}, x = \frac{- 1 - 21}{10}

ln (x 1 + x^{2})

x^{3} - 3 x^{2} + 25 x - 75

- 4 y = 4 y - 32

x^{4} - x

- m + 0.02 + 2.1 m = - 1.45 - 4.81 m

What are the solutions to the equation 5x^2+x-1=0 ?
The solutions to the equation 5x^2+x-1=0 are x=(-1+sqrt(21))/(10),x=(-1-sqrt(21))/(10)
Find the zeros of 5x^2+x-1=0
The zeros of 5x^2+x-1=0 are x=(-1+sqrt(21))/(10),x=(-1-sqrt(21))/(10)