What is ((x^2y^3)/(x^{-4)y^9})^2 ?

The solution to ((x^2y^3)/(x^{-4)y^9})^2 is (x^{12})/(y^{12)}

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simplify ((x^2y^3)/(x^{-4)y^9})^2

simplify

(\frac{x ^{2} y ^{3}}{x ^{- 4} y ^{9}})^{2}

\frac{x ^{12}}{y ^{12}}

Solution steps

(\frac{x ^{2} y ^{3}}{x ^{- 4} y ^{9}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{2} y ^{3} ) ^{2}}{( x ^{- 4} y ^{9} ) ^{2}}

Simplify

(x^{2} y^{3})^{2} : x^{4} y^{6}

= \frac{x ^{4} y ^{6}}{( x ^{- 4} y ^{9} ) ^{2}}

Simplify

(x^{- 4} y^{9})^{2} : \frac{y ^{18}}{x ^{8}}

= \frac{x ^{4} y ^{6}}{\frac{y ^{18}}{x ^{8}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{x ^{4} y ^{6} x ^{8}}{y ^{18}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{y ^{6}}{y ^{18}} = \frac{1}{y ^{18 - 6}}

= \frac{x ^{8} x ^{4}}{y ^{18 - 6}}

Subtract the numbers:

18 - 6 = 12

= \frac{x ^{8} x ^{4}}{y ^{12}}

x^{8} x^{4} = x^{12}

= \frac{x ^{12}}{y ^{12}}

10 - 3 y = 13

7 x - 2 \cdot (x + 1) = 0

∣ 2 x - 3 ∣ = 17

∣ 3 x - 4 ∣ = ∣ 2 x + 3 ∣

(2 - 3 i) (4 + 7 i)

What is ((x^2y^3)/(x^{-4)y^9})^2 ?
The solution to ((x^2y^3)/(x^{-4)y^9})^2 is (x^{12})/(y^{12)}