What is 4^{x+2}-5*4_{=}^x99 ?

The solution to 4^{x+2}-5*4_{=}^x99 is 4^{x+2}-495*4^x

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simplify 4^{x+2}-5*4_{=}^x99

simplify

4^{x + 2} - 5 \cdot 4_{=}^{x} 99

4^{x + 2} - 495 \cdot 4^{x}

Solution steps

4^{x + 2} - 5 \cdot 4^{x} \cdot 99

Multiply the numbers:

5 \cdot 99 = 495

= 4^{x + 2} - 495 \cdot 4^{x}

x 2 - 6 y

- 4 \times \frac{1}{4}

\frac{5 + 6 i}{- 1 + 8 i}

\frac{2}{3} \times 1

60 + 10 b

What is 4^{x+2}-5*4_{=}^x99 ?
The solution to 4^{x+2}-5*4_{=}^x99 is 4^{x+2}-495*4^x