What is (4-3i)/(-1+2i) ?

The solution to (4-3i)/(-1+2i) is -2-i

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simplify (4-3i)/(-1+2i)

simplify

\frac{4 - 3 i}{- 1 + 2 i}

- 2 - i

Solution steps

\frac{4 - 3 i}{- 1 + 2 i}

Multiply by the conjugate

\frac{- 1 - 2 i}{- 1 - 2 i}

= \frac{( 4 - 3 i ) ( - 1 - 2 i )}{( - 1 + 2 i ) ( - 1 - 2 i )}

Simplify

\frac{( 4 - 3 i ) ( - 1 - 2 i )}{( - 1 + 2 i ) ( - 1 - 2 i )} : \frac{- 10 - 5 i}{5}

= \frac{- 10 - 5 i}{5}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 10}{5} + \frac{- 5}{5} i

Simplify

\frac{- 10}{5} + \frac{- 5}{5} i : - 2 - i

= - 2 - i

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3 c + 9 d + 7 c + 5 d

x (3)

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