What are the solutions to the equation (x+4)^3-(x-3)^3=343 ?

The solutions to the equation (x+4)^3-(x-3)^3=343 are x=3,x=-4

Find the zeros of (x+4)^3-(x-3)^3=343

The zeros of (x+4)^3-(x-3)^3=343 are x=3,x=-4

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(x + 4)^{3} - (x - 3)^{3} = 343

x = 3, x = - 4

Solution steps

(x + 4)^{3} - (x - 3)^{3} = 343

Expand

(x + 4)^{3} - (x - 3)^{3} : 21 x^{2} + 21 x + 91

21 x^{2} + 21 x + 91 = 343

Move

343

to the left side

21 x^{2} + 21 x - 252 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 21 ( - 252 )}{2 \cdot 21}

2 1^{2} - 4 \cdot 21 (- 252) = 147

x_{1, 2} = \frac{- 21 \pm 147}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- 21 + 147}{2 \cdot 21}, x_{2} = \frac{- 21 - 147}{2 \cdot 21}

x = \frac{- 21 + 147}{2 \cdot 21} : 3

x = \frac{- 21 - 147}{2 \cdot 21} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

u^{2} + 8 u + 7

4 x + \frac{1}{4} = 10 x - \frac{x}{2}

3 (x + 1) + 11 < - 2 (x + 13)

21 z^{2} + 85 z - 26 = 0

4 y - (- 2 y - 3) = 9

What are the solutions to the equation (x+4)^3-(x-3)^3=343 ?
The solutions to the equation (x+4)^3-(x-3)^3=343 are x=3,x=-4
Find the zeros of (x+4)^3-(x-3)^3=343
The zeros of (x+4)^3-(x-3)^3=343 are x=3,x=-4