What is (2i-1)^2(4/(1-i)+(2-i)/(1+i)) ?

The solution to (2i-1)^2(4/(1-i)+(2-i)/(1+i)) is -11/2-23/2 i

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simplify (2i-1)^2(4/(1-i)+(2-i)/(1+i))

simplify

(2 i - 1)^{2} (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

- \frac{11}{2} - \frac{23}{2} i

Solution steps

(2 i - 1)^{2} (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

Expand

(2 i - 1)^{2} : - 4 i - 3

= (- 4 i - 3) (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

Apply FOIL method

(- 4 i - 3) (\frac{4}{1 - i} + \frac{2 - i}{1 + i}) : - \frac{11}{2} - \frac{23}{2} i

= - \frac{11}{2} - \frac{23}{2} i

\frac{- 1 + 2 i}{- 1 - 2 i}

\frac{2 ( - 0.49 ) + 1}{\frac{1}{4} - ( - 0.49 ) ^{2}}

\frac{2 x}{3} + 5 = \frac{5 x}{3} + 2

(\frac{1}{2})^{15}

\frac{3}{5} + \frac{4}{5}

What is (2i-1)^2(4/(1-i)+(2-i)/(1+i)) ?
The solution to (2i-1)^2(4/(1-i)+(2-i)/(1+i)) is -11/2-23/2 i