What is 8i\times (-9)i\times 6i ?

The solution to 8i\times (-9)i\times 6i is 432i

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simplify 8i\times (-9)i\times 6i

simplify

8 i \cdot (- 9) i \cdot 6 i

432 i

Solution steps

8 i (- 9) i 6 i

Multiply the numbers:

8 (- 9) \cdot 6 = - 432

= - 432 iii

Apply exponent rule:

aaa = a^{3}

iii = i^{3}

= - 432 i^{3}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

i^{3} = i^{2} i

= - 432 i^{2} i

Apply imaginary number rule:

i^{2} = - 1

= - 432 (- 1 i)

Apply rule:

1 \cdot a = a

- 1 i = - i

= - 432 (- i)

Apply rule:

- a (- b) = ab

- 432 (- i) = 432 i

= 432 i

\frac{1}{2} + \frac{1}{3}

(2 x - 10) (2 x - 8)

\frac{26}{65}

(2 x + 1) (2 x^{2} + 5 x - 4)

- 1 \times x^{2}

What is 8i\times (-9)i\times 6i ?
The solution to 8i\times (-9)i\times 6i is 432i