What is expand (x-1)\times (x+1) ?

The solution to expand (x-1)\times (x+1) is x^2-1

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expand (x-1)\times (x+1)

expand

(x - 1) \cdot (x + 1)

x^{2} - 1

Solution steps

(x - 1) (x + 1)

Apply Difference of Two Squares

(x - 1) (x + 1) : x^{2} - 1

= x^{2} - 1

(2 e^{\frac{t}{2}})^{2}

35 - 20

5 lo g_{25} (49)

5 \times 1 0^{- 6}

2 x^{2} \times 2

What is expand (x-1)\times (x+1) ?
The solution to expand (x-1)\times (x+1) is x^2-1