What are the solutions to the equation 3b^2-27b=0 ?

The solutions to the equation 3b^2-27b=0 are b=9,b=0

Find the zeros of 3b^2-27b=0

The zeros of 3b^2-27b=0 are b=9,b=0

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3 b^{2} - 27 b = 0

b = 9, b = 0

Solution steps

3 b^{2} - 27 b = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 27)^{2} - 4 \cdot 3 \cdot 0 = 27

b_{1, 2} = \frac{- ( - 27 ) \pm 27}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- ( - 27 ) + 27}{2 \cdot 3}, b_{2} = \frac{- ( - 27 ) - 27}{2 \cdot 3}

b = \frac{- ( - 27 ) + 27}{2 \cdot 3} : 9

b = \frac{- ( - 27 ) - 27}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

b = 9, b = 0

x^{4} x^{2}

e^{i (\frac{π}{4})}

\frac{1}{1 + 1}

1 2^{2} + 9^{2} = x^{2}

x^{2} - 6 x + 73 = 0

What are the solutions to the equation 3b^2-27b=0 ?
The solutions to the equation 3b^2-27b=0 are b=9,b=0
Find the zeros of 3b^2-27b=0
The zeros of 3b^2-27b=0 are b=9,b=0