What is factor+2n^2-3n-9 ?

The solution to factor+2n^2-3n-9 is (2n+3)(n-3)

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factor+2n^2-3n-9

factor

+ 2 n^{2} - 3 n - 9

(2 n + 3) (n - 3)

Solution steps

2 n^{2} - 3 n - 9

Break the expression into groups

= (2 n^{2} + 3 n) + (- 6 n - 9)

Factor out

n

from

2 n^{2} + 3 n : n (2 n + 3)

Factor out

- 3

from

- 6 n - 9 : - 3 (2 n + 3)

= n (2 n + 3) - 3 (2 n + 3)

Factor out common term

2 n + 3

= (2 n + 3) (n - 3)

\frac{2}{x} + \frac{1}{x + 1} - 3

3 - 6 x

(2 x - 5) (3 x^{2} - 5 x - 4)

\frac{2 π}{\frac{4 π}{5}}

20 \times 5