What is expand (2x-7)(2x^2+4x+3) ?

The solution to expand (2x-7)(2x^2+4x+3) is 4x^3-6x^2-22x-21

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x-7)(2x^2+4x+3)

expand

(2 x - 7) (2 x^{2} + 4 x + 3)

4 x^{3} - 6 x^{2} - 22 x - 21

Solution steps

(2 x - 7) (2 x^{2} + 4 x + 3)

Distribute parentheses

= 2 x \cdot 2 x^{2} + 2 x \cdot 4 x + 2 x \cdot 3 - 7 \cdot 2 x^{2} - 7 \cdot 4 x - 7 \cdot 3

Simplify

2 x \cdot 2 x^{2} + 2 x \cdot 4 x + 2 x \cdot 3 - 7 \cdot 2 x^{2} - 7 \cdot 4 x - 7 \cdot 3 : 4 x^{3} - 6 x^{2} - 22 x - 21

= 4 x^{3} - 6 x^{2} - 22 x - 21

(6 + 4 i)^{2}

9 \times 18

9 \times (- 5)

\frac{1}{6} - \frac{1}{15}

(2 x - 3) (3 x - 7)

What is expand (2x-7)(2x^2+4x+3) ?
The solution to expand (2x-7)(2x^2+4x+3) is 4x^3-6x^2-22x-21