What is expand (2x+5)(x^2-4x-1) ?

The solution to expand (2x+5)(x^2-4x-1) is 2x^3-3x^2-22x-5

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expand (2x+5)(x^2-4x-1)

expand

(2 x + 5) (x^{2} - 4 x - 1)

2 x^{3} - 3 x^{2} - 22 x - 5

Solution steps

(2 x + 5) (x^{2} - 4 x - 1)

Distribute parentheses

= 2 x x^{2} + 2 x (- 4 x) + 2 x (- 1) + 5 x^{2} + 5 (- 4 x) + 5 (- 1)

Simplify

2 x x^{2} + 2 x (- 4 x) + 2 x (- 1) + 5 x^{2} + 5 (- 4 x) + 5 (- 1) : 2 x^{3} - 3 x^{2} - 22 x - 5

= 2 x^{3} - 3 x^{2} - 22 x - 5

5^{3 x}

lo g_{0.2} (0.04)

3 x \times 4

3 lo g_{\frac{1}{2}} (x)

(3 x + 1) (2 x^{2} - 2 x - 9)

What is expand (2x+5)(x^2-4x-1) ?
The solution to expand (2x+5)(x^2-4x-1) is 2x^3-3x^2-22x-5