What is log_{10}(25)+log_{10}(40) ?

The solution to log_{10}(25)+log_{10}(40) is 3

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simplify log_{10}(25)+log_{10}(40)

simplify

lo g_{10} (25) + lo g_{10} (40)

3

Solution steps

lo g_{10} (25) + lo g_{10} (40)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (25) + lo g_{10} (40) = lo g_{10} (25 \cdot 40)

= lo g_{10} (25 \cdot 40)

Multiply the numbers:

25 \cdot 40 = 1000

= lo g_{10} (1000)

Factor the number:

1000 = 1 0^{3}

= lo g_{10} (1 0^{3})

Apply log rule:

lo g_{a} (a^{b}) = b

= 3

(2 x + 1) (- 2 x^{2} - x - 1)

\frac{9 33}{27 11}

6 \times (- 6)

\frac{1}{3} \times (- 6)

8 \times 8 \times 8 \times 8

What is log_{10}(25)+log_{10}(40) ?
The solution to log_{10}(25)+log_{10}(40) is 3