What are the solutions to the equation x^2+16x-17=0 ?

The solutions to the equation x^2+16x-17=0 are x=1,x=-17

Find the zeros of x^2+16x-17=0

The zeros of x^2+16x-17=0 are x=1,x=-17

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x^{2} + 16 x - 17 = 0

x = 1, x = - 17

Solution steps

x^{2} + 16 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 17) = 18

x_{1, 2} = \frac{- 16 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 18}{2 \cdot 1}, x_{2} = \frac{- 16 - 18}{2 \cdot 1}

x = \frac{- 16 + 18}{2 \cdot 1} : 1

x = \frac{- 16 - 18}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = 1, x = - 17

3 x \leq 15

x 2 = 4

2 r^{2} - 98 = 0

2 b^{2} - 28 b + 98

x^{3} - 6 x^{2} + 5 x

What are the solutions to the equation x^2+16x-17=0 ?
The solutions to the equation x^2+16x-17=0 are x=1,x=-17
Find the zeros of x^2+16x-17=0
The zeros of x^2+16x-17=0 are x=1,x=-17