What is factor x^4+2x^3+x^2+8x-12 ?

The solution to factor x^4+2x^3+x^2+8x-12 is (x-1)(x+3)(x^2+4)

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factor x^4+2x^3+x^2+8x-12

factor

x^{4} + 2 x^{3} + x^{2} + 8 x - 12

(x - 1) (x + 3) (x^{2} + 4)

Solution steps

x^{4} + 2 x^{3} + x^{2} + 8 x - 12

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 2 x ^{3} + x ^{2} + 8 x - 12}{x - 1}

\frac{x ^{4} + 2 x ^{3} + x ^{2} + 8 x - 12}{x - 1} = x^{3} + 3 x^{2} + 4 x + 12

= (x - 1) (x^{3} + 3 x^{2} + 4 x + 12)

Factor

x^{3} + 3 x^{2} + 4 x + 12 : (x + 3) (x^{2} + 4)

= (x - 1) (x + 3) (x^{2} + 4)

21 \times 2

21 \times 4

17 \times 8

- 3 \times (- 8)

What is factor x^4+2x^3+x^2+8x-12 ?
The solution to factor x^4+2x^3+x^2+8x-12 is (x-1)(x+3)(x^2+4)