What is expand (2x+3)(x^2-6x+1) ?

The solution to expand (2x+3)(x^2-6x+1) is 2x^3-9x^2-16x+3

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expand (2x+3)(x^2-6x+1)

expand

(2 x + 3) (x^{2} - 6 x + 1)

2 x^{3} - 9 x^{2} - 16 x + 3

Solution steps

(2 x + 3) (x^{2} - 6 x + 1)

Distribute parentheses

= 2 x x^{2} + 2 x (- 6 x) + 2 x \cdot 1 + 3 x^{2} + 3 (- 6 x) + 3 \cdot 1

Simplify

2 x x^{2} + 2 x (- 6 x) + 2 x \cdot 1 + 3 x^{2} + 3 (- 6 x) + 3 \cdot 1 : 2 x^{3} - 9 x^{2} - 16 x + 3

= 2 x^{3} - 9 x^{2} - 16 x + 3

lo g_{\frac{1}{3}} (13)

\frac{4}{x} + \frac{3}{x + 5}

5 x^{2} + 13 x + 6 - 4 x^{2} + 11 x + 8

(x^{2} - 5 x - 3) (3 x - 5)

75 + 45

What is expand (2x+3)(x^2-6x+1) ?
The solution to expand (2x+3)(x^2-6x+1) is 2x^3-9x^2-16x+3