What is expand (2x-5)(x^2-4x+4) ?

The solution to expand (2x-5)(x^2-4x+4) is 2x^3-13x^2+28x-20

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expand (2x-5)(x^2-4x+4)

expand

(2 x - 5) (x^{2} - 4 x + 4)

2 x^{3} - 13 x^{2} + 28 x - 20

Solution steps

(2 x - 5) (x^{2} - 4 x + 4)

Distribute parentheses

= 2 x x^{2} + 2 x (- 4 x) + 2 x \cdot 4 - 5 x^{2} - 5 (- 4 x) - 5 \cdot 4

Simplify

2 x x^{2} + 2 x (- 4 x) + 2 x \cdot 4 - 5 x^{2} - 5 (- 4 x) - 5 \cdot 4 : 2 x^{3} - 13 x^{2} + 28 x - 20

= 2 x^{3} - 13 x^{2} + 28 x - 20

2 x^{3} - 2 x^{2}

\frac{9 x ^{6} y ^{2}}{27 x y ^{2}}

(3 x + 4) (3 x - 5)

lo g_{4} (169)

\frac{280}{46}

What is expand (2x-5)(x^2-4x+4) ?
The solution to expand (2x-5)(x^2-4x+4) is 2x^3-13x^2+28x-20