What is x^{-1}\times x^{-1} ?

The solution to x^{-1}\times x^{-1} is 1/(x^2)

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simplify x^{-1}\times x^{-1}

simplify

x^{- 1} \cdot x^{- 1}

\frac{1}{x ^{2}}

Solution steps

x^{- 1} x^{- 1}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{- 1} x^{- 1} = x^{- 1 - 1}

= x^{- 1 - 1}

Subtract the numbers:

- 1 - 1 = - 2

= x^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= \frac{1}{x ^{2}}

(2 x - 4 y + 3)^{2}

- \frac{3}{4} - \frac{3}{4}

\frac{1}{12} - \frac{1}{2} + \frac{2}{3}

\frac{x ^{2}}{x - 3} - \frac{6 x - 9}{x - 3}

5 \times 18