What is (x^2-2x-63)/(x^2+3x-28) ?

The solution to (x^2-2x-63)/(x^2+3x-28) is (x-9)/(x-4)

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simplify (x^2-2x-63)/(x^2+3x-28)

simplify

\frac{x ^{2} - 2 x - 63}{x ^{2} + 3 x - 28}

\frac{x - 9}{x - 4}

Solution steps

\frac{x ^{2} - 2 x - 63}{x ^{2} + 3 x - 28}

Factor

x^{2} - 2 x - 63 : (x + 7) (x - 9)

= \frac{( x + 7 ) ( x - 9 )}{x ^{2} + 3 x - 28}

Factor

x^{2} + 3 x - 28 : (x - 4) (x + 7)

= \frac{( x + 7 ) ( x - 9 )}{( x - 4 ) ( x + 7 )}

Cancel the common factor:

x + 7

= \frac{x - 9}{x - 4}

\frac{2}{7} + \frac{6}{10}

\frac{1}{\frac{x}{1}}

9 \div \frac{3}{5}

6 \times 6 \times 6 \times 6 \times 6

\frac{12}{4 - 10}

What is (x^2-2x-63)/(x^2+3x-28) ?
The solution to (x^2-2x-63)/(x^2+3x-28) is (x-9)/(x-4)