What is the answer to 8(t+2)-3(t-4)=6(t-7)+8 ?

The answer to 8(t+2)-3(t-4)=6(t-7)+8 is t=62

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8(t+2)-3(t-4)=6(t-7)+8

8 (t + 2) - 3 (t - 4) = 6 (t - 7) + 8

t = 62

Solution steps

8 (t + 2) - 3 (t - 4) = 6 (t - 7) + 8

Expand

8 (t + 2) - 3 (t - 4) : 5 t + 28

Expand

6 (t - 7) + 8 : 6 t - 34

5 t + 28 = 6 t - 34

Move

28

to the right side

5 t = 6 t - 62

Move

6 t

to the left side

- t = - 62

Divide both sides by

- 1

t = 62

g - 6 \geq 2

\frac{7 r ^{4} s ^{6} t ^{7}}{9 r ^{1} s ^{2} t ^{8}}

18 x^{2} - 50

3 a x + 8 b - 6 b x - 4 a

3 (x + 2) + 2 x = 7 (x - 1) + 9

What is the answer to 8(t+2)-3(t-4)=6(t-7)+8 ?
The answer to 8(t+2)-3(t-4)=6(t-7)+8 is t=62
Solve for t: 8(t+2)-3(t-4)=6(t-7)+8
The solution is t=62