What is expand (x+4)(x+3)(x-1) ?

The solution to expand (x+4)(x+3)(x-1) is x^3+6x^2+5x-12

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expand (x+4)(x+3)(x-1)

expand

(x + 4) (x + 3) (x - 1)

x^{3} + 6 x^{2} + 5 x - 12

Solution steps

(x + 4) (x + 3) (x - 1)

Expand

(x + 4) (x + 3) (x - 1) : (x^{2} + 7 x + 12) (x - 1)

= (x^{2} + 7 x + 12) (x - 1)

Distribute parentheses

= x^{2} x + x^{2} (- 1) + 7 xx + 7 x (- 1) + 12 x + 12 (- 1)

Simplify

x^{2} x + x^{2} (- 1) + 7 xx + 7 x (- 1) + 12 x + 12 (- 1) : x^{3} + 6 x^{2} + 5 x - 12

= x^{3} + 6 x^{2} + 5 x - 12

\frac{6 + 2 i}{6 - 3 i}

121 - 49 x^{2}

1.2 \div \frac{1}{\frac{1}{1.2}}

\frac{9 x}{2} - \frac{2 x}{9}

\frac{38}{9}

What is expand (x+4)(x+3)(x-1) ?
The solution to expand (x+4)(x+3)(x-1) is x^3+6x^2+5x-12