What are the solutions to the equation (-8/17)^2+y^2=1 ?

The solutions to the equation (-8/17)^2+y^2=1 are y= 15/17 ,y=-15/17

Find the zeros of (-8/17)^2+y^2=1

The zeros of (-8/17)^2+y^2=1 are y= 15/17 ,y=-15/17

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(- \frac{8}{17})^{2} + y^{2} = 1

y = \frac{15}{17}, y = - \frac{15}{17}

Solution steps

(- \frac{8}{17})^{2} + y^{2} = 1

Expand

(- \frac{8}{17})^{2} + y^{2} : \frac{64}{289} + y^{2}

\frac{64}{289} + y^{2} = 1

Move

\frac{64}{289}

to the right side

y^{2} = 1 - \frac{64}{289}

Simplify

1 - \frac{64}{289} : \frac{225}{289}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{225}{289}, y = - \frac{225}{289}

\frac{225}{289} = \frac{15}{17}

- \frac{225}{289} = - \frac{15}{17}

y = \frac{15}{17}, y = - \frac{15}{17}

15 > - 5 w

0.74 = \frac{( x - 50 )}{7}

4 x - 7 > 17

- 2 x - 5 = 3

What are the solutions to the equation (-8/17)^2+y^2=1 ?
The solutions to the equation (-8/17)^2+y^2=1 are y= 15/17 ,y=-15/17
Find the zeros of (-8/17)^2+y^2=1
The zeros of (-8/17)^2+y^2=1 are y= 15/17 ,y=-15/17