What is 60a+64>= 80a-9260a+64>= 80a-92 ?

The solution to 60a+64>= 80a-9260a+64>= 80a-92 is 0<= a<= 39/2315

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60a+64>= 80a-9260a+64>= 80a-92

60 a + 64 \geq 80 a - 9260 a + 64 \geq 80 a - 92

0 \leq a \leq \frac{39}{2315}

Interval Notation

[0, \frac{39}{2315}]

Decimal Notation

0 \leq a \leq 0.01684 \dots

Solution steps

60 a + 64 \geq 80 a - 9260 a + 64 \geq 80 a - 92

a \geq u \geq b

then

a \geq u and u \geq b

60 a + 64 \geq 80 a - 9260 a + 64 and 80 a - 9260 a + 64 \geq 80 a - 92

60 a + 64 \geq 80 a - 9260 a + 64 : a \geq 0

80 a - 9260 a + 64 \geq 80 a - 92 : a \leq \frac{39}{2315}

Combine the intervals

a \geq 0 and a \leq \frac{39}{2315}

Merge Overlapping Intervals

0 \leq a \leq \frac{39}{2315}

k^{2} + k - 2

3^{2} \cdot 3^{4}

6^{2}

\frac{3}{8} \cdot \frac{12}{15}

What is 60a+64>= 80a-9260a+64>= 80a-92 ?
The solution to 60a+64>= 80a-9260a+64>= 80a-92 is 0<= a<= 39/2315