What are the solutions to the equation x^2+6x=12 ?

The solutions to the equation x^2+6x=12 are x=-3+sqrt(21),x=-3-sqrt(21)

Find the zeros of x^2+6x=12

The zeros of x^2+6x=12 are x=-3+sqrt(21),x=-3-sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 6 x = 12

x = - 3 + 21, x = - 3 - 21

Decimal Notation

x = 1.58257 \dots, x = - 7.58257 \dots

Solution steps

x^{2} + 6 x = 12

Move

12

to the left side

x^{2} + 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 12) = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 21}{2 \cdot 1}

x = \frac{- 6 + 2 21}{2 \cdot 1} : - 3 + 21

x = \frac{- 6 - 2 21}{2 \cdot 1} : - 3 - 21

The solutions to the quadratic equation are:

x = - 3 + 21, x = - 3 - 21

\frac{5}{3 - 2 i}

3 x^{2} + 4 x

3 x + 11 \leq 6 x + 8

125 - 27 x^{3}

What are the solutions to the equation x^2+6x=12 ?
The solutions to the equation x^2+6x=12 are x=-3+sqrt(21),x=-3-sqrt(21)
Find the zeros of x^2+6x=12
The zeros of x^2+6x=12 are x=-3+sqrt(21),x=-3-sqrt(21)