What is expand-2(3x+1)(x+2)(x-3) ?

The solution to expand-2(3x+1)(x+2)(x-3) is -6x^3+4x^2+38x+12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-2(3x+1)(x+2)(x-3)

expand

- 2 (3 x + 1) (x + 2) (x - 3)

- 6 x^{3} + 4 x^{2} + 38 x + 12

Solution steps

- 2 (3 x + 1) (x + 2) (x - 3)

Expand

- 2 (3 x + 1) (x + 2) (x - 3) : - 2 (3 x^{2} + 7 x + 2) (x - 3)

= - 2 (3 x^{2} + 7 x + 2) (x - 3)

Expand

- 2 (x - 3) : - 2 x + 6

= (- 2 x + 6) (3 x^{2} + 7 x + 2)

Distribute parentheses

= - 2 x \cdot 3 x^{2} - 2 x \cdot 7 x - 2 x \cdot 2 + 6 \cdot 3 x^{2} + 6 \cdot 7 x + 6 \cdot 2

Simplify

- 2 x \cdot 3 x^{2} - 2 x \cdot 7 x - 2 x \cdot 2 + 6 \cdot 3 x^{2} + 6 \cdot 7 x + 6 \cdot 2 : - 6 x^{3} + 4 x^{2} + 38 x + 12

= - 6 x^{3} + 4 x^{2} + 38 x + 12

1.44

245

(r - t)^{4}

\frac{5 x}{2} - x

6.02 \times 1 0^{23}

What is expand-2(3x+1)(x+2)(x-3) ?
The solution to expand-2(3x+1)(x+2)(x-3) is -6x^3+4x^2+38x+12