What is (9-10i)/(9+i) ?

The solution to (9-10i)/(9+i) is 71/82-99/82 i

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simplify (9-10i)/(9+i)

simplify

\frac{9 - 10 i}{9 + i}

\frac{71}{82} - \frac{99}{82} i

Solution steps

\frac{9 - 10 i}{9 + i}

Multiply by the conjugate

\frac{9 - i}{9 - i}

= \frac{( 9 - 10 i ) ( 9 - i )}{( 9 + i ) ( 9 - i )}

Simplify

\frac{( 9 - 10 i ) ( 9 - i )}{( 9 + i ) ( 9 - i )} : \frac{71 - 99 i}{82}

= \frac{71 - 99 i}{82}

Rewrite in standard complex form:

\frac{71}{82} - \frac{99}{82} i

= \frac{71}{82} - \frac{99}{82} i

x^{4} - 13 x^{2} + 36

- 0.5 (0.7 q - 0.9) + 2 q

1 \times i

\frac{5}{6} \times 2

(- 0.2 b^{6})^{3} 5 b