What is factor 2x^3-7x^2+12x+8 ?

The solution to factor 2x^3-7x^2+12x+8 is (2x+1)(x^2-4x+8)

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factor 2x^3-7x^2+12x+8

factor

2 x^{3} - 7 x^{2} + 12 x + 8

(2 x + 1) (x^{2} - 4 x + 8)

Solution steps

2 x^{3} - 7 x^{2} + 12 x + 8

Use the rational root theorem

= (2 x + 1) \frac{2 x ^{3} - 7 x ^{2} + 12 x + 8}{2 x + 1}

\frac{2 x ^{3} - 7 x ^{2} + 12 x + 8}{2 x + 1} = x^{2} - 4 x + 8

= (2 x + 1) (x^{2} - 4 x + 8)

\frac{18}{30}

lo g_{5} (125) - lo g_{3} (27) \times lo g_{4} (64)

10 \cdot 10 \cdot 10

(8 + 3 i) (8 + 3 i)

a \times 1

What is factor 2x^3-7x^2+12x+8 ?
The solution to factor 2x^3-7x^2+12x+8 is (2x+1)(x^2-4x+8)