What are the solutions to the equation 3x^2-5x+5=0 ?

The solutions to the equation 3x^2-5x+5=0 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6

Find the zeros of 3x^2-5x+5=0

The zeros of 3x^2-5x+5=0 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6

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3 x^{2} - 5 x + 5 = 0

x = \frac{5}{6} + i \frac{35}{6}, x = \frac{5}{6} - i \frac{35}{6}

Solution steps

3 x^{2} - 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 \cdot 5 : 35 i

x_{1, 2} = \frac{- ( - 5 ) \pm 35 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 35 i}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 35 i}{2 \cdot 3}

x = \frac{- ( - 5 ) + 35 i}{2 \cdot 3} : \frac{5}{6} + i \frac{35}{6}

x = \frac{- ( - 5 ) - 35 i}{2 \cdot 3} : \frac{5}{6} - i \frac{35}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} + i \frac{35}{6}, x = \frac{5}{6} - i \frac{35}{6}

\frac{2 ( 1 - 2 i ) - 3}{( 1 - 2 i ) - 1}

- 5 x \geq 30

5 x + 12 = 0

\frac{s ^{5} t ^{3}}{s ^{7} t ^{2}}

- \frac{1}{2} x \leq \frac{- 9}{4} + \frac{7}{5} x

What are the solutions to the equation 3x^2-5x+5=0 ?
The solutions to the equation 3x^2-5x+5=0 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6
Find the zeros of 3x^2-5x+5=0
The zeros of 3x^2-5x+5=0 are x= 5/6+i(sqrt(35))/6 ,x= 5/6-i(sqrt(35))/6