What is (7b)/(b+2)-3/(b+5) ?

The solution to (7b)/(b+2)-3/(b+5) is (7b^2+32b-6)/((b+2)(b+5))

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simplify (7b)/(b+2)-3/(b+5)

simplify

\frac{7 b}{b + 2} - \frac{3}{b + 5}

\frac{7 b ^{2} + 32 b - 6}{( b + 2 ) ( b + 5 )}

Solution steps

\frac{7 b}{b + 2} - \frac{3}{b + 5}

Least Common Multiplier of

b + 2, b + 5 : (b + 2) (b + 5)

Adjust Fractions based on the LCM

= \frac{7 b ( b + 5 )}{( b + 2 ) ( b + 5 )} - \frac{3 ( b + 2 )}{( b + 2 ) ( b + 5 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{7 b ( b + 5 ) - 3 ( b + 2 )}{( b + 2 ) ( b + 5 )}

Simplify

7 b (b + 5) - 3 (b + 2) : 7 b^{2} + 32 b - 6

= \frac{7 b ^{2} + 32 b - 6}{( b + 2 ) ( b + 5 )}

23 \cdot 27

27 \times 7

80 \times 245

\frac{3}{y + 3} + \frac{2 y}{y ^{2} + 8 x + 15}

1 + \frac{1}{2} + \frac{1}{4}

What is (7b)/(b+2)-3/(b+5) ?
The solution to (7b)/(b+2)-3/(b+5) is (7b^2+32b-6)/((b+2)(b+5))