What are the solutions to the equation 6y^2-y-1=0 ?

The solutions to the equation 6y^2-y-1=0 are y= 1/2 ,y=-1/3

Find the zeros of 6y^2-y-1=0

The zeros of 6y^2-y-1=0 are y= 1/2 ,y=-1/3

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6 y^{2} - y - 1 = 0

y = \frac{1}{2}, y = - \frac{1}{3}

Decimal Notation

y = 0.5, y = - 0.33333 \dots

Solution steps

6 y^{2} - y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 1) = 5

y_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 6}, y_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 6}

y = \frac{- ( - 1 ) + 5}{2 \cdot 6} : \frac{1}{2}

y = \frac{- ( - 1 ) - 5}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = - \frac{1}{3}

\frac{x}{6} + 4 = 12

- 8 + [2 x + 6] = 1

\frac{2}{( 1000 )} (278.548) - 2 (- 9.8) (13)

5 c^{2} - 17 c + 14

15 x - 2 = 4 x - 13

What are the solutions to the equation 6y^2-y-1=0 ?
The solutions to the equation 6y^2-y-1=0 are y= 1/2 ,y=-1/3
Find the zeros of 6y^2-y-1=0
The zeros of 6y^2-y-1=0 are y= 1/2 ,y=-1/3