What is factor x^4+2x^3-9x^2-2x+8 ?

The solution to factor x^4+2x^3-9x^2-2x+8 is (x-1)(x+1)(x-2)(x+4)

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factor x^4+2x^3-9x^2-2x+8

factor

x^{4} + 2 x^{3} - 9 x^{2} - 2 x + 8

(x - 1) (x + 1) (x - 2) (x + 4)

Solution steps

x^{4} + 2 x^{3} - 9 x^{2} - 2 x + 8

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 2 x ^{3} - 9 x ^{2} - 2 x + 8}{x - 1}

\frac{x ^{4} + 2 x ^{3} - 9 x ^{2} - 2 x + 8}{x - 1} = x^{3} + 3 x^{2} - 6 x - 8

= (x - 1) (x^{3} + 3 x^{2} - 6 x - 8)

Factor

x^{3} + 3 x^{2} - 6 x - 8 : (x + 1) (x - 2) (x + 4)

= (x - 1) (x + 1) (x - 2) (x + 4)

x^{3} - 6 x^{2} + 61 x - 106

\frac{1}{16} + \frac{1}{2}

8 x^{2} + 2 x

x^{33}

What is factor x^4+2x^3-9x^2-2x+8 ?
The solution to factor x^4+2x^3-9x^2-2x+8 is (x-1)(x+1)(x-2)(x+4)