What are the solutions to the equation x^2+18x+81=25 ?

The solutions to the equation x^2+18x+81=25 are x=-4,x=-14

Find the zeros of x^2+18x+81=25

The zeros of x^2+18x+81=25 are x=-4,x=-14

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x^{2} + 18 x + 81 = 25

x = - 4, x = - 14

Solution steps

x^{2} + 18 x + 81 = 25

Move

25

to the left side

x^{2} + 18 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 56 = 10

x_{1, 2} = \frac{- 18 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 10}{2 \cdot 1}, x_{2} = \frac{- 18 - 10}{2 \cdot 1}

x = \frac{- 18 + 10}{2 \cdot 1} : - 4

x = \frac{- 18 - 10}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = - 4, x = - 14

\frac{7}{100} x^{2} - \frac{y}{121}

\frac{\frac{1}{2}}{- \frac{1}{2}}

(\frac{n}{6} - \frac{6}{n})^{2}

m + 1 > 9

18 + 2 x < 12

What are the solutions to the equation x^2+18x+81=25 ?
The solutions to the equation x^2+18x+81=25 are x=-4,x=-14
Find the zeros of x^2+18x+81=25
The zeros of x^2+18x+81=25 are x=-4,x=-14